tag:blogger.com,1999:blog-5997147895880585179.post8601722717782234466..comments2022-01-23T00:41:47.969+05:30Comments on Solutions to I E Irodov - Physical Fundamentals of Mechanics: Irodov Problem 1.4Unknownnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-5997147895880585179.post-65781117222282397822012-05-24T10:31:52.677+05:302012-05-24T10:31:52.677+05:30so is there any way to find the equation of the cu...so is there any way to find the equation of the curve??sayantanpsychicdonhttps://www.blogger.com/profile/11636805280963476830noreply@blogger.comtag:blogger.com,1999:blog-5997147895880585179.post-69078828084695149562010-07-22T07:29:13.109+05:302010-07-22T07:29:13.109+05:30i support u krishna.how can we know at at exactly ...i support u krishna.how can we know at at exactly 16secs the tangent will pass through origin unless ,we don't know the the equation of the curve how can we determine the equation of the tangent at t=16 and say that the origin satisfies it?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5997147895880585179.post-44880585240996180412009-12-26T18:08:16.520+05:302009-12-26T18:08:16.520+05:30Thanks for the comment, I think the solution neede...Thanks for the comment, I think the solution needed more explanation. I have updated the solution and hopefully its clear now why I am saying the exact answer cannot be found unless the nature of the deceleration curve is known.Krishna Kant Chintalapudihttps://www.blogger.com/profile/07024636005277277405noreply@blogger.comtag:blogger.com,1999:blog-5997147895880585179.post-19305623687217857112009-12-22T15:38:17.313+05:302009-12-22T15:38:17.313+05:30Third part of the problem
Average velocity = slop...Third part of the problem<br /><br />Average velocity = slope of line joining point to the origin (since v_avg = s/t)<br />Instantaneous velocity = slope of the tangent to the curve at that point (since v_ins = ds / dt)<br />Only place where this happens is in the deceleration phase, as you pointed out.<br />Looking at the plot, t = 16s is the right place (at least to my eyes :-).Anonymousnoreply@blogger.com