Monday, May 19, 2008

Irodov Problem 1.163

There are no external forces acting on the (mass+disc) system in the horizontal direction and so the total momentum of the (mass disc) system will be conserved at all times. Initially the momentum of the system in the horizontal direction is mv. As soon as the disc starts to move up the curve, its starts to transfer it horizontal momentum to the mass. When the disc has completed the curve and is moving vertically upwards relative to the mass suppose that the mass has achieved a velocity v'. Since the disc is moving with the mass the net momentum of the (disc+mass) system in the horizontal direction will be (M+m)v'.
Hence applying conservation of momentum in the horizontal direction will be,

In addition to conservation of momentum, energy also will be conserved at all times. Initially since only the disc is moving, the total energy is the kinetic energy of the disc i.e. . When the disc leaves the mass and moves into the air it retains its horizontal component of velocity v'.
When it reaches its highest point in the air, it has no vertical component of velocity but has a horizontal component v'. The total energy of the system when the disc reaches it highest point is the sum of i) kinetic energy of the mass , ii) the kinetic energy of disc and iii) the gravitational potential energy gained by the disc mgh. Since energy must always be conserved,

1 comment:

kloba said...

Sir i aprecciate your studying physics and failed the first half-year...but i realised what are my priorities in my life and that i love physics,and irodov is my way to get back on track,so this means a LOT to me,tnx so much!!!!...btw this problem confused me a lot cause they first ask for starting speed of the bullet,and then the loss in energy...when solving (a) i took that loss into account and messed up everything,couldnt solve it...then i looked at your solution and just punched myself :)...tnx again.