Sunday, October 5, 2008

Irodov Problem 1.226

The satellite is moving very close to the Earth's surface, so we can assume that the radius of its orbit is almost equal to R - the radius of the Earth. Let the mass of Earth be M and its time period of rotation about its own axis be T. As already solved in problem 1.225, the angular velocity of the satellite w with respect to a stationary observer is given by irrespective of the direction (East to West or West to East) it moves. It absolute velocity is given by . The absolute velocity of an observer on Earth is given by . The velocity of the satellite as measured by an observer on Earth for the two satellites (moving East to West and West to East) will be v+vE and v-vE respectively. So the ratio of kinetic energies of the satellite (of mass m ) as perceived by an observer on Earth will be,

The exact numerical value can be computed by putting the values,

given by approximately 1.27.


prerna said...

Sir thanx for putting irodov solutions online . i really appreciate your work . the answers to solutions are really very good and througly explained . but it has been a quite a while and you havent uplopaded any of solutions from quite some time . so i request you to put the solutions regularly as i need them as i am preparing for IIT JEE.

manish said...

its great to see irodov solutions.
thanks for creating and uploading them.there is one request frm my side, that u please do write it at FASTER rate so that it would very helpful to me as well as my frnds......who r trying for IIT.

krishna_kant said...

dear Prerna, manish,

I am happy that my blog is helping you all.

I will try my best, but I have a job, a wife ... and last month has been quite busy for me with business travel and meeting some deadlines. I will get back to posting very soon.

I wish you all the best of luck with IIT.


Anonymous said...

sir please give me the solution of prob no.3.28 of irodov . I shall be obeliged to you.

krishna_kant said...

dear nandan,

check out solution to problem 1.215 for the gravitational field inside a spherical cavity. The solution for 3.28 is similar.

$1d d $uper$t@r said...

Awesome work sir, dese solns r really helping me in enhancing my concepts nd in level building. i must say thanks. !