Sunday, March 29, 2009

Irodov Problem 1.287

As the cylinder spins about the axis XX' it has an angular velocity Iw directed along the axis XX' . Now the axis XX' undergoes oscillations (Irodov means simple harmonic oscillations even though he does not specifically mention it in the problem).

This means that the angle of orientation of the axis XX' at some instant of time ifs given,

The angular momentum vector of the cylinder L, is thus, given by,

This change in angular momentum is provided by the torque resulting from the force acting at the bearings given by F(l/2) + F(l/2) = Fl. Hence, we have,

(see the list of moments of inertia)

No comments: