b) For this part of the problem we could use the result obtained from Problem 1.358 namely,
To obtain the velocity of particle 2 as seen from particle 1 we have to substitute V=v1 and vx = -v2 in the above equation. Hence, we obtain,
Saturday, November 21, 2009
Irodov Problem 1.359
a) The position of the particles as seen in the laboratory frame of reference are given by x1 = v1t and x2 = -v2t. The relative velocity is thus simple the time derivative of x1-x2 given by v1+v2.
b) For this part of the problem we could use the result obtained from Problem 1.358 namely,
To obtain the velocity of particle 2 as seen from particle 1 we have to substitute V=v1 and vx = -v2 in the above equation. Hence, we obtain,
b) For this part of the problem we could use the result obtained from Problem 1.358 namely,
To obtain the velocity of particle 2 as seen from particle 1 we have to substitute V=v1 and vx = -v2 in the above equation. Hence, we obtain,
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