Saturday, July 14, 2007

Irodov Problem 1.14



















After t seconds the train headlight has moved and later it will be . The taillight however, will be l units behind the head light so event 2 will occur at. The distance between the two events thus events are separated by,


.

If a frame is moving at speed V then, during time it will move a distance of V. This distance must exactly be equal to the separation of distance between the two events. Thus, the velocity of the frame should simply be,

6 comments:

siva said...

i did not understand the soln

krishna_kant said...

dear siva if you can tell me at which point in the solution you failed to understand I can try and answer you better

prattyrockstar said...

sir,
gd evenin, i dint undersand why u hav divided the equation by time 2.i think we hav to mltiply it na because we want to find out distance between those 2 events w.r.t reference frame train itself..

krishna_kant said...

All calculations in the problem are w.r.t a stationary frame of reference. Maybe I should draw a figure to explain the solution... let me work on it and try to make it clearer.

krishna_kant said...

ok I've added a small figure and changed the last equation to make things a bit more clearer. Hope this helps.

Anonymous said...

well done , i never thought that the solution of this question will be this simple , well i am nt so good at phy. , but this solution made me proud , i am happy to see this answer :)