Sunday, October 11, 2009

Irodov Problem 1.349

Let the original length of the rod (in a frame fixed to the rod) be l0. Also, let the length of the scale's unit be 1 as measured in the frame fixed to the rod.
Suppose that the rod is moving with velocity v relative to the scale.

In the reference frame fixed to the scale:

As seen from the scale, since the rod is moving it would appear smaller. Its length would be . Thus, as measured by the scale, the length of rod will be

In the reference frame fixed to the rod:

As seen from the frame fixed to the rod, the rod is stationary and has a length of l0 , however, the scale is moving with a velocity v. Thus, each unit of the scale will shrink and will be . Thus, when measured using the scale the measured length will be,

From (1) and (2) we have,

1 comment:

Anonymous said...

Great Work! Would like to talk to you, please write back to -

john dot aron dot smith at gmail

Looking forward to talking to you.